## What is the bond order of NF+?

2
Therefore, NF is predicted to be paramagnetic with a bond order of 2. The populations of the bonding (8 electrons) and antibonding (4 electrons) molecular orbitals in the diagram suggest a double bond.

## Is NF diatomic?

4. * (1997 1 7) Consider the diatomic molecule NF.

What is N in molecular orbital theory?

Basic structure of molecular orbital diagram for nitrogen is: Electrons of nitrogen are to be filled in this diagram. Left side represents the configuration of one atom of nitrogen molecule and the right side represents the second atom of nitrogen molecule. Atomic number of nitrogen is seven.

Is o2 paramagnetic or diamagnetic?

Due to the presence of two unpaired electrons, we can say that the oxygen molecule is paramagnetic in nature. The reason why oxygen is paramagnetic is because of the presence of two unpaired electrons.

### What is homonuclear and heteronuclear?

These diatomic molecules can be classified as either homonuclear, meaning that they contain two atoms of the same element, or heteronuclear, which requires that they be comprised of one atom of two different elements.

### Which is the correct bond order for NF?

Therefore, NF is predicted to be paramagnetic with a bond order of 2. The populations of the bonding (8 electrons) and antibonding (4 electrons) molecular orbitals in the diagram suggest a double bond. c. 2p, and 2p * orbitals exhibit Cv symmetry, with the NF bond axis the infinite-fold rotation axis.

Do you expect the ionization potential of NF to be greater than F?

C. Do you expect NF to be diamagnetic or paramagnetic? Why? NF is paramagnetic because of its two unpaired electrons. D. The ionization potential of N is 14.54 eV and that for F is 17.42 eV. Do you expect the ionization potential of NF to be greater than that of F, closer to N than F, closer to F than N, or less than N? Explain.

How is the CN energy level diagram similar to no?

The CN–energy level diagram is similar to that of NO (Problem 5.7) without the antibonding π* electron. b. The bond order is three, with no unpaired electrons. c. The HOMO is the 2porbital, which can interact with the 1s of the H+, as in the diagram at right.